## Similar Problems

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# Average Time Of Process Per Machine - Leetcode Solution

LeetCode: Average Time Of Process Per Machine Leetcode Solution

Difficulty: Easy

Topics: database

Problem Statement:

You are given an integer n, the number of machines in a factory. Each machine has a process time represented by an array of integers machines where machines[i] denotes the time it takes for the ith machine to complete its task.

The factory has a conveyor belt that can be used to move any machine to any other machine in the factory. The task of each machine can be processed in any order. However, each machine can only work on one task at a time. The conveyor belt is only used to move the machines.

You want to improve the efficiency of the factory, so you decide to minimize the time that each machine spends idle. You can do this by arranging the machines in a way that minimizes the average time that each machine spends idle.

Return the minimum possible average time that each machine spends idle.

Example:

Input: machines = [1,2,3] Output: 1.00000 Explanation: You can divide the machines into two groups: Group1: [1], process time = 1 Group2: [2, 3], process time = 5 The average idle time is (0 + 1) / 2 = 0.50000.

Solution:

The problem statement could be a little confusing at first, but if you understand the requirements correctly, then solving it is quite easy.

The first step is to calculate the total process time given by the machines and divide it by the number of machines. This will give us the initial threshold. We can use this as our starting point to check if the given solution is optimal or not.

Next, we can calculate the idle time for each machine when they are arranged in a particular order. We can check the idle time for each machine when they are maintained in the specific order.

One potential way to do this is to start with the smallest process time machine, arrange the rest of the machines in ascending order of their processing time, then iterate through this ordered array and calculate the idle time for each machine.

We can also start with the largest processing time machine, arrange the rest of the machines in descending order of their processing time, and iterate in reverse order to calculate idle time for each machine.

Once we have the ordering with the minimum idle time, we can calculate the average idle time for each machine and check if it is less than or equal to the threshold we obtained earlier.

If it satisfies this condition, then we have the optimal arrangement, and the answer is the average idle time we calculated. Otherwise, we need to modify the ordering and repeat the process until we find the optimal arrangement.

The following is the code implementation in Python:

def min_avg_time(machines):

n = len(machines) total_process_time = sum(machines) threshold = total_process_time / n current_order = sorted(machines) current_idle_time = 0

# start with the smallest processing time machine

for i in range(n-1): current_idle_time += current_order[i] - threshold current_order[i+1] += current_order[i] - threshold

# check if the current ordering is optimal, otherwise try reverse order

if current_idle_time <= 0: return threshold else: current_order = sorted(machines, reverse=True) current_idle_time = 0 for i in range(n-1): current_idle_time += current_order[i] - threshold current_order[i+1] += current_order[i] - threshold return (current_idle_time + total_process_time) / (2 * n)

The time complexity of this solution is O(nlogn) due to the sorting of the machines array. The space complexity is O(n) for the list used to keep track of the current ordering.

## Average Time Of Process Per Machine Solution Code

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