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Dice Roll Simulation - Leetcode Solution
Companies:
LeetCode: Dice Roll Simulation Leetcode Solution
Difficulty: Hard
Topics: dynamic-programming array
Problem Statement:
You have a standard dice that is 6-sided. You are asked to simulate a dice roll using a random number generator. Write a function to generate a random integer in the range of 1 to 6.
Solution:
Approach 1: Using the built-in random module of Python
Python has a built-in random module that provides functions for generating random numbers. We can use the randint function in the random module to generate a random integer in the given range. Here is the Python function to simulate a dice roll:
import random
def rollDice():
return random.randint(1, 6)
This function uses the randint function of the random module to generate a random integer in the range of 1 to 6. The function returns the generated integer as the result.
Approach 2: Using the numpy module of Python
Numpy is a third-party library for Python that provides support for arrays and numerical mathematics. We can use the randint function in the numpy module to generate a random integer in the given range. Here is the Python function to simulate a dice roll using numpy:
import numpy as np
def rollDice():
return np.random.randint(1, 7)
This function uses the randint function of the numpy module to generate a random integer in the range of 1 to 6. The function returns the generated integer as the result.
Approach 3: Using the random number generator of C++
If we want to simulate a dice roll in a C++ program, we can use the random number generator of the C++ standard library. Here is the C++ function to simulate a dice roll:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int rollDice() {
srand(time(0));
return (rand() % 6) + 1;
}
int main() {
cout << "Dice roll result: " << rollDice() << endl;
return 0;
}
This function uses the srand function to seed the random number generator with the current time. The rand function is then used to generate a random integer in the range of 0 to 5. We add 1 to the result to get the final result in the range of 1 to 6. The function returns the generated integer as the result.
Dice Roll Simulation Solution Code
1You are given an array of integers nums and an integer target. Return the number of ways you can "roll" the dice so that the sum of the dice faces is equal to target.
2
3Constraints:
4
51 <= nums.length <= 1000
61 <= nums[i] <= 6
71 <= target <= 1000
8
9// Solution:
10
11int numRollsToTarget(vector<int>& nums, int target) {
12 // Base case:
13 if (target == 0) return 1;
14
15 // Recursive case:
16 int ans = 0;
17 for (int i = 0; i < nums.size(); i++) {
18 // If the current face value is <= target, recurse
19 if (nums[i] <= target) {
20 ans += numRollsToTarget(nums, target - nums[i]);
21 }
22 }
23 return ans;
24}