Find The Index Of The Large Integer - Leetcode Solution

Problem Statement:

Given a list of non-negative integers nums, find the largest integer and return its index. If there are multiple largest integers, return the index of the first one.

Example 1:

Input: nums = [3,6,1,0] Output: 1 Explanation: The largest integer is 6 and its index is 1.

Example 2:

Input: nums = [1,2,3,4] Output: 3 Explanation: The largest integer is 4 and its index is 3.

Solution:

To solve the problem, we need to traverse the given list and find the maximum integer. As we traverse, we will keep track of the index of the maximum integer. We will update the index whenever we find a new maximum integer. Once we have traversed the whole list, we will return the index of the maximum integer.

Algorithm:

1. Initialize a variable 'maxVal' as 0 and a variable 'maxIndex' as 0. These variables will store the maximum value and its index respectively.
2. Traverse the list 'nums' using a for loop.
3. For each element in the list, compare it with 'maxVal'.
4. If the element is greater than 'maxVal', update the values of both 'maxVal' and 'maxIndex'.
5. Continue the loop until all the elements in the list are compared.
6. Return 'maxIndex' as the answer.

Pseudo Code:

maxVal, maxIndex = 0, 0 for i from 0 to len(nums) - 1 do if nums[i] > maxVal then maxVal = nums[i] maxIndex = i end if end for return maxIndex

Time Complexity:

The time complexity of the algorithm is O(n) because we need to traverse the list 'nums' only once.

Space Complexity:

The space complexity of the algorithm is O(1) because we are not using any extra space to store the elements of the list. We are only using two extra variables 'maxVal' and 'maxIndex' to keep track of the maximum value and its index.

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