Number Of Burgers With No Waste Of Ingredients - Leetcode Solution

Problem Summary: We have two ingredients, a tomato slice and a cheese slice. We need to make a certain number of burgers with these ingredients. We do not want any waste of ingredients, which means we must use all the tomato and cheese slices. We need to find out how many burgers can be made without any waste of ingredients.

Solution Approach: Let's consider that we have “n” tomato slices and “m” cheese slices. To make a burger, we need one slice of tomato and one slice of cheese. Therefore, if we want to create "x" number of burgers, we need “x” slices of each ingredient, which is equivalent to "2x" slices in total. Therefore, we can create a maximum of "min(n, m/2)" burgers.

To understand this better, let’s consider the following example: Suppose we have 17 tomato slices and 8 cheese slices. In this case, we can only make 4 burgers because we will run out of cheese after making the 4th burger.

In the case where we do not have enough tomato slices to make the maximum number of burgers, we need to reduce the number of burgers to the maximum number of burgers we can make using the available tomato slices. For example, if we have 5 tomato slices and 12 cheese slices, we can make at most 2 burgers because we will run out of tomato slices after the second burger.

Code Implementation in Python: Here’s the code implementation in Python to solve this problem:

def numOfBurgers(tomatoSlices: int, cheeseSlices: int) -> List[int]: # Maximum number of burgers we can make. max_burgers = min(tomatoSlices // 2, cheeseSlices)

# Check if we have any leftover tomato slices.
if tomatoSlices - max_burgers * 2 == 0:
    return [max_burgers, 0]

# Check if we have any leftover cheese slices.
if cheeseSlices - max_burgers == 0:
    return [0, max_burgers]

# If we have any left-over slices, we can't make any burgers.
return []

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