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Number Of Different Integers In A String - Leetcode Solution
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LeetCode: Number Of Different Integers In A String Leetcode Solution
Difficulty: Easy
Topics: string hash-table
Problem Statement:
Given a string s containing only digits, return the number of different integers that can be formed by deleting some (possibly zero) characters from s and not changing the relative order of the remaining characters.
Example: Input: s = "a123bc34d8ef34" Output: 3 Explanation: The three different integers are "123", "34", and "834".
Solution:
To solve this problem, we need to iterate through the string s and count the number of different integers that can be formed by deleting some characters and maintaining their relative order. We can do this by maintaining a set of all the different integers we have encountered so far.
Algorithm:
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Create an empty set called integer_set to store all the different integers we encounter while iterating through the string.
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Initialize a variable called current_number to an empty string.
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Iterate through the string s character by character.
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If the current character c is a digit, append it to the string current_number.
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If the current character c is not a digit, then check if the string current_number is not empty. If it is not empty, then add the current_number to the set integer_set and reset the string current_number to an empty string.
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After iterating through the entire string, check if the string current_number is not empty. If it is not empty, then add the current_number to the set integer_set.
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Return the size of the set integer_set.
Python code:
class Solution: def numDifferentIntegers(self, s: str) -> int:
# Step 1
integer_set = set()
# Step 2
current_number = ""
# Step 3
for c in s:
# Step 4
if c.isdigit():
current_number += c
# Step 5
else:
if current_number:
integer_set.add(int(current_number))
current_number = ""
# Step 6
if current_number:
integer_set.add(int(current_number))
# Step 7
return len(integer_set)
Number Of Different Integers In A String Solution Code
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