Number Of Students Doing Homework At A Given Time - Leetcode Solution

The problem "Number Of Students Doing Homework At A Given Time" on LeetCode asks us to count the number of students who are doing their homework at a given time. We are given the start time and end time for each student's homework and the target time we need to find the number of students for.

To solve this problem, we need to iterate over each student's start and end times and check if the target time falls within that interval. If it does, we increase our counter of the number of students doing their homework by 1.

Here's a step-by-step solution to the problem:

1. Initialize a counter variable to 0 to count the number of students doing their homework at the target time.

2. Iterate over each student's start and end times. For each student:

   a. Check if the target time falls within the student's homework interval. If it does, increase the counter variable by 1.

3. Return the counter variable as the final answer.

Here's the Python code for the solution:

def busyStudent(startTime, endTime, queryTime):
    count = 0
    for i in range(len(startTime)):
        if startTime[i] <= queryTime <= endTime[i]:
            count += 1
    return count

In this solution, we are using a for loop to iterate over each student's start and end times using the range() function. We are then checking if the target time falls within the current student's interval using the <= operator. If it does, we increase our counter variable by 1. Finally, we return the count variable as the final answer.

In summary, to solve the "Number Of Students Doing Homework At A Given Time" problem on LeetCode, we need to iterate over each student's start and end times and count the number of students who are doing their homework at the target time. This can be done using a simple for loop and checking if the target time falls within each student's interval.

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